qiskit.aqua.algorithms.HHLResult.update¶

HHLResult.update(*args, **kwargs)¶

If E present and has a .keys() method, does: for k in E: D[k] = E[k] If E present and lacks .keys() method, does: for (k, v) in E: D[k] = v In either case, this is followed by: for k, v in F.items(): D[k] = v