Source code for qiskit.circuit.library.templates.nct.template_nct_9d_8

# This code is part of Qiskit.
#
# (C) Copyright IBM 2020.
#
# This code is licensed under the Apache License, Version 2.0. You may
# obtain a copy of this license in the LICENSE.txt file in the root directory
# of this source tree or at http://www.apache.org/licenses/LICENSE-2.0.
#
# Any modifications or derivative works of this code must retain this
# copyright notice, and modified files need to carry a notice indicating
# that they have been altered from the originals.

"""
Template 9d_8:
.. parsed-literal::
    q_0: ──■────■────■────■─────────■────■─────────■──
           │    │  ┌─┴─┐  │       ┌─┴─┐  │       ┌─┴─┐
    q_1: ──■────┼──┤ X ├──┼────■──┤ X ├──┼────■──┤ X ├
         ┌─┴─┐┌─┴─┐└─┬─┘┌─┴─┐┌─┴─┐└─┬─┘┌─┴─┐┌─┴─┐└─┬─┘
    q_2: ┤ X ├┤ X ├──■──┤ X ├┤ X ├──■──┤ X ├┤ X ├──■──
         └───┘└───┘     └───┘└───┘     └───┘└───┘
"""

from qiskit.circuit.quantumcircuit import QuantumCircuit


def template_nct_9d_8():
    """
    Returns:
        QuantumCircuit: template as a quantum circuit.
    """
    qc = QuantumCircuit(3)
    qc.ccx(0, 1, 2)
    qc.cx(0, 2)
    qc.ccx(0, 2, 1)
    qc.cx(0, 2)
    qc.cx(1, 2)
    qc.ccx(0, 2, 1)
    qc.cx(0, 2)
    qc.cx(1, 2)
    qc.ccx(0, 2, 1)
    return qc